The problem is that you pass the condition as a string and not as a real condition, so R can't evaluate it when you want it to. It is possible to add both scalar and vector attributes to datasets. The data elements must be of the same basic type. Speed vs Velocity. You can vote up the ones you like or vote down the ones you don't like, and go to the original project or source file by following the links above each example. The variances are along the diagonal of C. The norm of a vector is its length, and the length of a vector must always be positive (or zero). You may choose to create a new dataset to store the result, or you may simply keep the result as a standard matrix. n=length(y) model_a1 <- auto.arima(y) plot(x=1:n,y,xaxt="n",xlab="") axis(1,at=seq(1,n,length.out=20),labels=index(y)[seq(1,n,length.out=20)], las=2,cex.axis=.5) lines(fitted(model_a1), col = 2) The result depending on your data will be something similar: ... You are just saving a map into variable and not displaying it. install.packages('rJava') library(rJava) .jinit() jObj=.jnew("JClass") result=.jcall(jObj,"[D","method1") Here, JClass is a Java class that should be in your ClassPath environment variable, method1 is a static method of JClass that returns double[], [D is a JNI notation for a double array. R: Using the “names” function on a dataset created within a loop, How to quickly read a large txt data file (5GB) into R(RStudio) (Centrino 2 P8600, 4Gb RAM), Rbind in variable row size not giving NA's, Subsetting rows by passing an argument to a function. In this case, the error, 'height' must be a vector or a matrix is telling you you didn't give the plot function what it wanted. hist(x) creates a histogram bar chart of the elements in vector x.The elements in x are sorted into 10 equally spaced bins along the x-axis between the minimum and maximum values of x. hist displays bins as rectangles, such that the height of each rectangle indicates the number of elements in the bin.. collapse is the Stata equivalent of R's aggregate function, which produces a new dataset from an input dataset by applying an aggregating function (or multiple aggregating functions, one per variable) to every variable in a dataset. library("scales") library(ggplot2) reverselog_trans <- function(base = exp(1)) { trans <- function(x) -log(x, base) inv <- function(x) base^(-x) trans_new(paste0("reverselog-", format(base)), trans, inv, log_breaks(base = base), domain = c(1e-100, Inf)) }... R prefers to use i rather than j. Aslo note that complex is different than as.complex and the latter is used for conversion. In linux, you could use awk with fread or it can be piped with read.table. I think you want to minimize the square of a-fptotal ... ff <- function(x) myfun(x)^2 > optimize(ff,lower=0,upper=30000) $minimum [1] 28356.39$objective [1] 1.323489e-23 Or find the root (i.e. Since all single annotations have same height, the value of simple_anno_size is a single unit value. Combining the example by @Robert and code from the answer featured here: How to get a reversed, log10 scale in ggplot2? In that case given legend labels should correspond to the rows of height; if legend.text is true, the row names of height will be used as labels if they are non-null. We reproduce a memory representation of the matrix in R with the matrix function. I think the issue might be that you are trying to pass a DataFrame as the height parameter. For single matrix input, C has size [size(A,2) size(A,2)] based on the number of random variables (columns) represented by A.The variances of the columns are along the diagonal. In this case, the error, 'height' must be a vector or a matrix is telling you you didn't give the plot function what it wanted. The best selection of Royalty Free Height Vector Art, Graphics and Stock Illustrations. R cannot tell which variable is which when you pass it an entire data.frame to plot. If all # annotation_height are absolute units, height is ignored # 2. if annotation height contains non-absolute units, height also need to be set and the # non-absolute unit should be set in a simple form such as 1:10 or unit(1, "null") A feature vector is a vector containing multiple elements about an object. A matrix is usually delimited by square brackets. Velocity is speed with a direction. Otherwise... You can try cSplit library(splitstackshape) setnames(cSplit(mergedDf, 'PROD_CODE', ','), paste0('X',1:4))[] # X1 X2 X3 X4 #1: PRD0900033 PRD0900135 PRD0900220 PRD0900709 #2: PRD0900097 PRD0900550 NA NA #3: PRD0900121 NA NA NA #4: PRD0900353 NA NA NA #5: PRD0900547 PRD0900614 NA NA Or using the devel version of data.table i.e. I think this code should produce the plot you want. If you only have 4 GBs of RAM you cannot put 5 GBs of data 'into R'. Also, thanks to akrun for the test data. This should only take a vector or a matrix. You can try something like this: barplot(as.matrix(data), beside=T , legend.text=T, col=c("red" , "green", "blue"), ylim=c(0,140), ylab="height") Hopefully this helps you out. If you read on the R help page for as.Date by typing ?as.Date you will see there is a default format assumed if you do not specify. For some reason the top and bottom margins need to be negative to line up perfectly. I think the issue might be that you are trying to pass a DataFrame as the height parameter. In your case, you're getting the values 2 and 4 and then trying to index your vector again using its own values. If height is a matrix and beside is FALSE then each bar of the plot corresponds to a column of height, with the values in the column giving the heights of stacked sub-bars'' making up the bar. Either k or h must be non-NULL, if both are non-NULL then k is used and h is ignored. I'll leave that to you. ## Create input input <- names<-(lapply(landelist, function(x) sample(0:1, 1)), landelist) filterland <- c() for (landeselect in landelist) if (input[[landeselect]] == TRUE) # use [[... some reproducible code would allow me to give you some example code, but in the absence of that... wrap what you currently have in another if(), checking for length = 0 (or just && it, with the NULL check first), and display your favorite placeholder message.... A better approach would be to read the files into a list of data.frames, instead of one data.frame object per file. Fixed my typo in the first matrix. This is only useful when height is a matrix. The operation can then be applied to the matrix. Your sapply call is applying fun across all values of x, when you really want it to be applying across all values of i. it's better to generate all the column data at once and then throw it into a data.frame. This is my first general solution and I want to put it in vector form. R cannot tell which variable is which when you pass it an entire data.frame to plot. Barplot coming back with 'height must be a vector or matrix' Aliyah Bartoletti posted on 15-11-2020 r I've put in my x and y variables as Try.. zz <- lapply(z,copy) zz[[1]][ , newColumn := 1 ] Using your original code, you will see that applying copy() to the list does not make a copy of the original data.table. Thus (6,2,−1)+(4,0) is not deﬁned, and (4,0,−1) = (4,0) makes no sense at all. F = fillmissing(A,'constant',v) fills missing entries of an array or table with the constant value v.If A is a matrix or multidimensional array, then v can be either a scalar or a vector. Notation. The following are 30 code examples for showing how to use cv2.getRotationMatrix2D().These examples are extracted from open source projects. Turned out much more complex and cryptic than I'd been hoping, but I'm pretty sure it works. Using data.table library(data.table) setDT(df1)[, list(pages=paste(page, collapse="_")), list(user_id, date=as.Date(date, '%m/%d/%Y'))] Or using dplyr library(dplyr) df1 %>% group_by(user_id, date=as.Date(date, '%m/%d/%Y')) %>% summarise(pages=paste(page, collapse='_')) ... copy() is for copying data.table's. To get the sapply to do what I assume you want to do, you can do the following: sapply(X = 1:length(x), FUN = fun, x =... You can put your records into a data.frame and then split by the cateogies and then run the correlation for each of the categories. radians indicates whether or not input angles are given in radians (True) or degrees (False; the default). Scalar and Vector Attributes. I simply want the graph to compare the numbers in a bar stacked side by side.I have not been able to achieve that. Since the oth_let1 vector has only two members, you get NA.... Use [[ or [ if you want to subset by string names, not $. The height of the simple annotation is controlled by simple_anno_size argument. Download 9,500+ Royalty Free Height Vector Images. library(reshape2) #ggplot needs a dataframe data <- as.data.frame(data) #id variable for position in matrix data$id <- 1:nrow(data) #reshape to long format plot_data <- melt(data,id.var="id") #plot ggplot(plot_data, aes(x=id,y=value,group=variable,colour=variable)) + geom_point()+ geom_line(aes(lty=variable))... Do not use the dates in your plot, use a numeric sequence as x axis. ; Saying Ariel the Dog runs at 9 km/h (kilometers per hour) is a speed.. But saying he runs 9 km/h Westwards is a velocity.. See Speed and Velocity to learn more.. You can do myStr <- "0.76+0.41j" myStr_complex <- as.complex(sub("j","i",myStr)) Im(myStr_complex) # [1] 0.41 ... You can try library(data.table)#v1.9.4+ setDT(yourdf)[, .N, by = A] ... You can do it with rJava package. It's generally not a good idea to try to add rows one-at-a-time to a data.frame. A matrix is a two-dimensional array that has a fixed number of rows and columns and contains a number at the intersection of each row and column. \begin{cases} x1 &= .5x4\\ x2 &= x4\\ x3 &= .5x4\\ x4 & \text{is free}\\ \end{cases} Here is the matrix I pulling the information from just in case you need it. If A is a row or column vector, C is the scalar-valued variance.. For two-vector or two-matrix input, C is the 2-by-2 covariance matrix between the two random variables. You can use the dates as labels. From Hadley's Advanced R, "x$y is equivalent to x[["y", exact = FALSE]]." If h is a vector of numbers, the output will be a matrix with a column for each value in h. The default is NULL. It's easier to think of it in terms of the two exposures that aren't used, rather than the five that are. Height is a scalar when defining a constant value, i.e. Note there are arguments like width, height, annotation_width and annotation_height, but they are used to adjust the width/height for the complete heamtap annotations (which are always mix of several annotations). Instead, the dot operator must be used to get the desired data into a matrix. Groups are defined by the structure of the tree above the cut. The angles must be a column vector (i.e., numpy array). height: either a vector or matrix of values describing the bars which make up the plot. [on hold], How to plot data points at particular location in a map in R, How to build a 'for' loop with input$i in R Shiny. A negative length makes no sense. if you still want to pass it as string you need to parse and eval it in the right place for example: cond... Fitted values in R forecast missing date / time component, Convert strings of data to “Data” objects in R [duplicate], Keep the second occurrence in a column in R, Converting column from military time to standard time, Fitting a subset model with just one lag, using R package FitAR, Remove quotes to use result as dataset name, R: recursive function to give groups of consecutive numbers, How to split a text into two meaningful words in R. How (in a vectorized manner) to retrieve single value quantities from dataframe cells containing numeric arrays? Here's a solution for extracting the article lines only. You can do this with something like: get_scalar <- function(name, FUN=max) { sapply(mydata[,name], function(x) if(all(x == -999)) NA else FUN(as.numeric(x[x != -999]))) } Note that I've changed your function... r,function,optimization,mathematical-optimization. how to read a string as a complex number? A vector is a series of numbers, like a matrix with one column but multiple rows, that can often be represented spatially. the height at which to cut tree to produce the groups. If height is a vector, the plot consists of a sequence of rectangular bars with heights given by the values in the vector. The following is an example of a matrix with 2 rows and 3 columns. However, without your exact dataset, I had to generate simulated data. sz = size(A) returns a row vector whose elements are the lengths of the corresponding dimensions of A.For example, if A is a 3-by-4 matrix, then size(A) returns the vector [3 4].. A matrix having only one row is called a row vector. Essentially, the matrix is represented by a Cartesian coordinate system, in which the rows of the matrix are parallel to the x-axis and the columns to the y-axis of …